# Can dbt cloud use multiple redshift severless databases as sources?

**URL:** <https://discourse.getdbt.com/t/can-dbt-cloud-use-multiple-redshift-severless-databases-as-sources/13109>\
**Category:** Help\
**Created:** [April 29, 2024, 1:42pm UTC](https://discourse.getdbt.com/t/can-dbt-cloud-use-multiple-redshift-severless-databases-as-sources/13109 "2024-04-29T13:42:11Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![hseedat](https://avatars.discourse-cdn.com/v4/letter/h/96bed5/32.png) [@hseedat](https://discourse.getdbt.com/u/hseedat)\
**Post date:** [April 29, 2024, 1:42pm UTC](https://discourse.getdbt.com/t/can-dbt-cloud-use-multiple-redshift-severless-databases-as-sources/13109/1 "2024-04-29T13:42:11Z")

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I have two data sources, for example 2 different redshift severless workspaces, one with 8 nodes and one with 16 nodes.  
database\_1 and database\_2 are from the two respective redshift clusters.

I have a single dbt project and I need to read data from both datasources.  
my project has a sql\_1 model that uses database\_1 and it also has a sql\_2 model that uses database\_2 as the source.  
The lineage can be something like this, sql\_1 → sql\_2 etc.

Is this possible? Can I have two different database sources in a single project? and if so, how can I do it?

The reason I want to do this is because sql\_1 work works really well with an 8 node cluster and sql\_2 works really well with the 16 node cluster. They both have the same target database.

Any guidance would be really appreciated.  
We have an enterprise dbt cloud account.

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**Author:** ![B.agoimuvi97](https://avatars.discourse-cdn.com/v4/letter/b/df705f/32.png) [@B.agoimuvi97](https://discourse.getdbt.com/u/B.agoimuvi97)\
**Post date:** [May 21, 2024, 9:29pm UTC](https://discourse.getdbt.com/t/can-dbt-cloud-use-multiple-redshift-severless-databases-as-sources/13109/2 "2024-05-21T21:29:58Z")

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Can anyone answer this question? I’m looking for someone to answer because I have the same question. If anyone has solution, please tag me. Thanks a lot. ![](https://tubidy.diy)